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| 1 | +typedef long long ll; |
| 2 | +class Solution { |
| 3 | +public: |
| 4 | + // left: greater or equal |
| 5 | + // right: greater |
| 6 | + ll mod = 1e9 + 7; |
| 7 | + ll myPow(ll a, ll b) { |
| 8 | + ll res = 1; |
| 9 | + while (a) { |
| 10 | + if (a & 1) res = (res * b) % mod; |
| 11 | + a = a >> 1; |
| 12 | + b = b * b % mod; |
| 13 | + } |
| 14 | + return res; |
| 15 | + } |
| 16 | + int maximumScore(vector<int>& nums, int k) { |
| 17 | + int n = nums.size(); |
| 18 | + vector<int> prime(n, 0); |
| 19 | + for (int i = 0; i < nums.size(); i++) { |
| 20 | + int cnt = 0; |
| 21 | + int num = nums[i]; |
| 22 | + for (int j = 2; j * j <= num; j++) { |
| 23 | + cnt += (num % j) == 0; |
| 24 | + while ((num % j) == 0) num /= j; |
| 25 | + } |
| 26 | + if (num != 1) cnt += 1; |
| 27 | + prime[i] = cnt; |
| 28 | + } |
| 29 | + unordered_map<int, int> leftMap; |
| 30 | + unordered_map<int, vector<int>> rightMap; |
| 31 | + for (int i = n - 1; i >= 0; i--) { |
| 32 | + rightMap[prime[i]].push_back(i); |
| 33 | + } |
| 34 | + |
| 35 | + vector<pair<ll, ll>> record; |
| 36 | + for (ll i = 0; i < n; i++) { |
| 37 | + rightMap[prime[i]].pop_back(); |
| 38 | + ll leftLen = i + 1; |
| 39 | + for (int j = prime[i]; j <= 10; j++) |
| 40 | + if (leftMap.count(j)) |
| 41 | + leftLen = min(leftLen, i - leftMap[j]); |
| 42 | + ll rightLen = n - i; |
| 43 | + for (int j = prime[i] + 1; j <= 10; j++) |
| 44 | + if (rightMap.count(j) && rightMap[j].size() > 0) |
| 45 | + rightLen = min(rightLen, rightMap[j].back() - i); |
| 46 | + record.push_back({nums[i], leftLen * rightLen}); |
| 47 | + leftMap[prime[i]] = i; |
| 48 | + } |
| 49 | + sort(record.begin(), record.end(), greater<>()); |
| 50 | + |
| 51 | + ll ans = 1; |
| 52 | + for (auto &x: record) { |
| 53 | + ll tmp = myPow(min(x.second, 1ll * k), x.first); |
| 54 | + ans = (ans * tmp) % mod; |
| 55 | + k -= x.second; |
| 56 | + if (k <= 0) break; |
| 57 | + } |
| 58 | + return ans; |
| 59 | + } |
| 60 | +}; |
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